If P and Q are the points of trisection of the line joining A(2, -2) and B(-7, 4) such that P is nearer to A, then the coordinates of P and Q are:
∵ Point P is near to A.
∴ P(x1,y1) divides AB in the ratio 1 : 2, while Q(x2,y2) divides AB in the ratio 2 : 1.
section formula;
P(x,y)=m1x2+m2x1m1+m2,m1y2+m2y1m1+m2
Thus, by section formula,
P(x1,y1)=(−7+4)3,(4−4)3=(−1,0)
Q(x2,y2)=(−14+2)3,(8−2)3=(−4,2)
Hence, coordinates of point P is (−1,0) and point Q is (−4,2).