If $P_{a t m}$ = 0 mm Hg and $P_{a l v}$ = -2 mm Hg, then

it is the end of the normal inspiration and there is no airflow

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it is the end of the normal expiration and there is no airflow

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transpulmonary pressure (

P_{t p}

) is -2 mm Hg

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air is flowing into the lungs.

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Solution

The correct option is C air is flowing into the lungs.
If alveolar pressure ( $P_{a l v}$ ) is negative with respect to atmospheric pressure ( $P_{a t m}$ ), then driving force for airflow is inward i.e., from the atmosphere into the lungs.

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If Patm = 0 mm Hg and Palv = -2 mm Hg, then

The correct option is C air is flowing into the lungs.If alveolar pressure (Palv) is negative with respect to atmospheric pressure (Patm), then driving force for airflow is inward i.e., from the atmosphere into the lungs.

If $P_{a t m}$ = 0 mm Hg and $P_{a l v}$ = -2 mm Hg, then

The correct option is C air is flowing into the lungs.
If alveolar pressure ( $P_{a l v}$ ) is negative with respect to atmospheric pressure ( $P_{a t m}$ ), then driving force for airflow is inward i.e., from the atmosphere into the lungs.