The correct option is A T,F,F
p→(q∨r) is false.
∴p is true; q∨r is false.
⇒p is true; q is false; r is false.
Alternate Solution :
pqrq∨rp→q∨rTTTTTTTFTTTFTTTTFFFFFTTTTFTFTTFFTTTFFFFT
Clearly, from truth table, p→(q∨r) is false when truth values of statements p,q,r are T,F,F respectively.