Question

If $p\left(x\right)=1+7x-9x^2+\frac{2}{3}{x}^3$, then $p(-3)=$

• A. $-81$
• B. $-137$
• C. $-119$
• D. $-100$

Answer 1

The correct option is C $-119$

Consider the polynomial $p\left(x\right)=1+7x-9x^2+\frac{2}{3}{x}^3$ and substitute $x=-3$ in the polynomial:

$p(-3)=1+(7\times -3)-9(-3{)}^2+\frac{2}{3}(-3{)}^3=1-21-(9\times 9)+(\frac{2}{3}\times -27)=1-21-81-18=-119$

Hence, $p(-3)=-119$.