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Question

If P(x)=a0+a1x2+a2x4+.......+anx2n be a polynomial in xR with 0<a1<a2<.......<an, then P(x) has-

A
no point of minimum
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B
only one point of minimum
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C
only two points of minimum
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D
None of these
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Solution

The correct option is B only one point of minimum
Given P(x)=a0+a1x2+a2x4+.......+anx2n
P(x)=2xa1+4a2x3+.......+2nanx2n1
For max. or min. P(x)=0
2x[a1+2a2x2+.......+n.anx2n2]=0
x=0
Now P′′(x)=2a1+12a2x2+........+2n(2n1)anx2n2
P′′(x)=2a1>0 (given a1>0)
Hence, P(x) has only one minimum at x=0

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