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Byju's Answer
Standard XI
Mathematics
Integration by Parts
If Φ x=limn→∞...
Question
If
Φ
(
x
)
=
lim
n
→
∞
x
n
−
x
−
n
x
n
+
x
−
n
,
0
<
x
<
1
,
ϵ
N
, then
∫
(
s
i
n
−
1
x
)
(
Φ
(
x
)
)
d
x
is equal to
A
x
s
i
n
−
1
(
x
)
+
√
1
−
x
2
+
C
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B
−
(
x
s
i
n
−
1
(
x
)
+
√
1
−
x
2
)
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C
x
s
i
n
−
1
x
+
√
1
−
x
2
+
C
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D
None of these
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Solution
The correct option is
A
x
s
i
n
−
1
(
x
)
+
√
1
−
x
2
+
C
We have
ϕ
(
x
)
=
lim
n
→
∞
x
2
n
−
1
x
2
n
+
1
=
1
,
0
<
x
<
1
∴
∫
s
i
n
−
1
x
.
ϕ
(
x
)
d
x
=
∫
s
i
n
−
1
x
d
x
=
[
x
s
i
n
−
1
x
+
√
1
−
x
2
]
+
c
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0
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