If points (1,2,3) , (0,-4,3) , (2,3,5) and (1,-5,-3) are vertices of tetrahedron then the point where lines joining the mid-point of opposite edges are concurrent is
(a)

(1,-1,2)

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(-1,1,2)

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(1,1,-2)

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(-1,1,-2)

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Solution

The correct option is A (1,-1,2)
Line joining midpoint of opposite edge are concurrent at center of tetrahedron
$\begin{matrix} (\frac{1 + 0 + 2 + 1}{4}, \frac{2 - 4 + 3 - 5}{4}, \frac{3 + 3 + 5 - 3}{4}) (1, - 1, 2) H e n c e, t h e c o r r e c t o p t i o n i s (A) \end{matrix}$

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