Question

If potassium chlorate is 80% pure,then 48g of oxygen would be produced from

a)153.12g of Kclo3. B)122.5g of KCLO3

c) 245g of KCLO3. d) 98.0 g of KCLO3

Answer 1

Firstly on writing the balanced equation we get-

2KClO3→ 2KCl + 3O2

From here we can say that,

245g (2 moles) of KClO3gives Oxygen = 96g

So, 1 g of KClO3will give Oxygen = 96/245 g

Hence, 122.5g of KClO3will give Oxygen = 96/245 x 122.5

= 48 g

We know that, the KClO3is 80% pure.

So, 48g of Oxygen will be produced by amount of 80% pure KClO3= 122.5/48 *48*100/80g

= 153.125 g

Hence answer is option a)

Hope this helps :)