If pressure of CO 2 real gas in a container is given by P - RT -2 V - b - a -4 b 2 then mass of the gas in container isA- 22 gmB- 33 gmC- 11 gmD- 44 gm

The correct option is A 22 gmVander wall's gas equation for m mole of real gas ( P+μ^2 a/V^2 )(V μ b)=μ RT ⇒ P=μ RT/V μ b μ^2 a/V^2 on comparing the given equ ...

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Standard XII

Chemistry

Dalton's Law of Partial Pressures

If pressure o...

Question

If pressure of $C O_{2}$ (real gas) in a container is given by $P = \frac{R T}{2 V - b} - \frac{a}{4 b^{2}}$ then mass of the gas in container is

11 gm

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22 gm

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33 gm

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44 gm

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Solution

The correct option is B 22 gm
Vander wall's gas equation for m mole of real gas
$(P + \frac{μ^{2} a}{V^{2}}) (V - μ b) = μ R T \Rightarrow P = \frac{μ R T}{V - μ b} - \frac{μ^{2} a}{V^{2}}$
on comparing the given equation with this standard equation we get $μ = \frac{1}{2}$ . Hence $μ = \frac{m}{M} \Rightarrow$ mass of gas
$m = μ m = \frac{1}{2} \times 44 = 22 g m .$

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If pressure of CO2 (real gas) in a container is given by P=RT2V−b−a4b2 then mass of the gas in container is

The correct option is B 22 gmVander wall's gas equation for m mole of real gas (P+μ2aV2)(V−μb)=μRT⇒P=μRTV−μb−μ2aV2 on comparing the given equation with this standard equation we get μ=12. Hence μ=mM⇒ mass of gas m=μm=12×44=22gm.

If pressure of $C O_{2}$ (real gas) in a container is given by $P = \frac{R T}{2 V - b} - \frac{a}{4 b^{2}}$ then mass of the gas in container is