wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If pressure of CO2 (real gas) in a container is given by P = RT2Vba4V2 then mass of the gas in container is

A
11 gm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
22 gm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
33 gm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
44 gm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 22 gm

Vander wal's gas equation for μ mole of real gas
(P + μ2αV2)(V - μb) = μRT P = μRTVμbμ2V2
on comparing the given equation with this standard equation we get μ=12. Hence μ = mM mass of gas
m = μM = 12×44 = 22gm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vapour
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon