Question

If $Pt$ in $PtC{l}_4.2HCl$ has a coordination number of 6, how many moles of $AgCl$ will 1 mole of the compound precipitate with excess $AgN{O}_3$ ?

• A. 0
• B. 1
• C. 2
• D. 4

Answer 1

The correct option is A 0

Since the coordination number is 6, the compound should have six groups linked to Pt atom in coordination sphere.
It already has six groups linked to it and cannot lose any $C{l}^{-}$ ion to form $AgCl$. Hence, no $AgCl$ will be produced.