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Question

If px4+qx3+rx2+sx+t=∣∣ ∣∣x2+3xx−1x+3x+12−xx−3x−3x+43x∣∣ ∣∣ then t is equal to

A
33
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B
0
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C
21
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D
none
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Solution

The correct option is C 21
Given, px4+qx3+rx2+sx+t=∣ ∣x2+3xx1x+3x+12xx3x3x+43x∣ ∣
Put x=0
t=∣ ∣013123340∣ ∣

On expanding the above determinant we get,
t=21
Hence, option C.

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