If p(x)=x3+3x2-2x+4 then find p(1) and p(-2)
Find the value of P
Given that P(x)=x3+3x2–2x+4
P(-2)=-23+3-22–2-2+4=-8+12+4+4=12
P(1)=13+312–21+4=1+3-2+4=6
Hence P(1) and P-2 are 6 and 12 respectively.
Question 4 On dividing x3−3x2+x+2 by a polynomial g(x), the quotient and remainder were x−2 and −2x+4, respectively. Find g(x).