Question

If $Q=2$ coulomb and force on it is $F=100$ newton, then the value of field intensity will be:

• A. $100$ $N/C$
• B. $50$ $N/C$
• C. $200$ $N/C$
• D. $10$ $N/C$

Answer 1

Answer: (B)

$50$ $N/C$

Answer is B.

Electric force on a charge q placed in a region of electric field intensity is E and it is given by $Eq$.
In this case, $F=100N$ and $q=2C$.
So, $E=\frac{F}{q}=\frac{100N}{2C}=50N/C$.
Hence, the value of field intensity will be $50$ N/C.