If Q (3, 1) is equidistant from P ( 5, -3) and R ( x 6), then positive value of x is

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none of the above

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Solution

The correct option is B 4
To find the $x$ - ordinate of R
$x = \frac{5 + 3}{2} = 8 / 2 = 4$
$∴ R = (4, 6)$

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