If R=0.01Ω, the magnitude and direction of current flowing in the loop are
A
1A, clockwise
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B
1A, anticlockwise
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C
10A, clockwise
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D
10A, anticlockwise
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E
none
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Solution
The correct option is B10A, clockwise
As the area of the loop goes to zero, the flux associated with it goes to zero. To calculate the induced current:-
Δϕ=BΔA=1×π×(0.1)2Tm2
Δt=0.314s
ξ=ΔϕΔt=1×3.14×0.010.314V
ξ=0.1V
I=ξR=0.10.01A=10A
To decide the direction, we can easily see that it will try to restore the flux in the direction inside the plane of paper and thereby by right hand thumb rule, we will get the direction as clockwise