MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Variation of g with Height

If 'R' is the...

Question

If 'R' is the radius of earth, the height from the surface at which the weight of a body becomes one-fourth of its weight, on the surface of earth is:

A

2R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

R

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

R/4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

R/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
R

We know, g = GM / R²

g_h ÷ g = GM ÷ R + h²× R²÷ GM

or, 1÷4g /g = R²÷ (R + h)²

R + h ÷ R = 2/1

1 + h÷R = 2

h÷R = 1

h=R

Suggest Corrections

thumbs-up

6

Similar questions

Q. If R is the radius of earth, the height at which the weight of a body becomes

1 / 4

its weight on the surface of earth is :

Q. The height from the center of the earth at which the weight of a body becomes

1 / 16^{th}

times its weight on the surface of the earth is -

R

is the radius of earth.

Q. The height at which the weight of a body becomes

\frac{1}{16} t h

, its weight on the surface of earth (radius

R

Q. The height at which the weight of a body becomes 1/16th its weight on the surface of earth (Radius R ) is:

Q. The weight of a body on surface of earth is

12.6 N

. When it is raised to a height half the radius of earth its weight will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Thyroid Gland

PHYSICS

Watch in App

explore_more_icon

Explore more

Variation of g with Height

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon