If relative permeability of iron is 2000. Its absolute permeability in S.I units is

8 π \times 10^{- 4}

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8 π \times 10^{- 3}

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800 / π

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8 π \times 10^{9} / π

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Solution

The correct option is B $8 π \times 10^{- 4}$
$μ = μ_{0} μ_{r} = (4 π \times 10^{- 7}) \times 2000 = 8 π \times 10^{- 4}$ S.I units

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