If resonant frequency is $f$ and capacitance become $4$ times, then resonant frequency will be :

\frac{f}{2}

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2 f

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f

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\frac{f}{4}

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Solution

The correct option is B $\frac{f}{2}$
Frequency, $f = \frac{1}{2 π \sqrt{L C}}$
When capacitance $= 4 C$ , then
$f^{'} = \frac{1}{2 π \sqrt{4 L C}} = \frac{f}{2}$ .

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