Question

The resonant frequency of a circuit is f. If the capacitance is made 16 times the initial values, then the resonant frequency will become

• A. $\frac{f}{2}$
• B. 2f
• C. f
• D. $\frac{f}{4}$

Answer 1

The correct option is D

$\frac{f}{4}$

$f=\frac{1}{2\pi \sqrt{LC}}\Rightarrow f\propto \frac{1}{\sqrt{C}}$