If rope of lift breaks suddenly, the tension exerted by the surface of lift (a=acceleration of lift)
If a body of mass m is carried by a lift moving with an upward acceleration a,then the forces acting on a body are (i) the reaction R on the floor of a lift upwards (ii) the weight mg of the body acting vertically downwards . The equation of motion will be given by
A)R=mg-ma
B)R=mg+ma
C)R=ma-mg
D)R=mg*ma
A body of weight 600N rests on the floor of a lift. The cable of the lift breaks and it suddenly starts falling freely. What will be the force exerted by the floor of the lift on this object?