If -S- is the surface area of the right circular cone whose h and - are the height and semi- vertical angle- S is equal to-

The correct option is D π h2 tanα secα Surface area of right cirular cone =π r I tan α =r/h ⇒ r =h tan α ⇒ cos α =h/I I =sec α h So, surface area of cone =π ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Refractive Index

If 'S' is the...

Question

If 'S' is the surface area of the right circular cone whose h and α are the height and semi- vertical angle, S is equal to-

π h² tanα cosα

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π h² tanα secα

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

π h² cosα sinα

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π h secα cotα

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
π h² tanα secα

Surface area of right cirular cone = $π r I$
$t a n α = \frac{r}{h}$
$\Rightarrow r = h t a n α$
$\Rightarrow c o s α = \frac{h}{I}$
$I = s e c α h$
So, surface area of cone = $π h t a n α . s e c α h$
= $π h^{2} t a n α s e c α$

Suggest Corrections

Similar questions

Q. Match list 1 and list 2.

List -I List -2

C O + H_{2}

1. Producer gas
B)

C O + N_{2}

2. Semi water gas
C)

C O + H_{2} + N_{2}

3. Water gas
D)

H_{2} + C H_{4} + C O

4. Coal gas

Q. In the figure, area of parallelogram is

64 m^{2} .

Its sides are 16 m and 8 m. Find the height

h_{1}

and

h_{2} .

In figure, area of parallelogram is

64 m^{2} .

Its sides are 16 m and 8 m.Find the height

h_{1} a n d h_{2} .

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

Q. Two projectiles are thrown with the same initial velocity at angles

α

and

(90^{\circ} - α)

with the horizontal. The maximum heights attained by them are

h_{1}

and

h_{2}

respectively. Then

\frac{h_{1}}{h_{2}}

is equal to

Join BYJU'S Learning Program

If 'S' is the surface area of the right circular cone whose h and α are the height and semi- vertical angle, S is equal to-

The correct option is B π h2 tanα secα Surface area of right cirular cone =πrI tan α=rh ⇒r=h tan α ⇒cos α=hI I=sec αh So, surface area of cone =π h tan α.sec α h =πh2 tan α sec α

The correct option is B
π h² tanα secα

Surface area of right cirular cone = $π r I$
$t a n α = \frac{r}{h}$
$\Rightarrow r = h t a n α$
$\Rightarrow c o s α = \frac{h}{I}$
$I = s e c α h$
So, surface area of cone = $π h t a n α . s e c α h$
= $π h^{2} t a n α s e c α$