If S+O2→SO2;ΔH=−398.2kJ;SO2+12O2→SO3;ΔH=−98.7kJ SO2+H2O→H2SO4;ΔH=−130.2kJ;H2+12O2→H2O;ΔH=−227.3kJ The enthalpy of formation of sulphuric acid at 298K will be?
A
−854.4kJ
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B
−754.4 kJ
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C
−650.3kJ
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D
−433.7kJ
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Solution
The correct option is A−854.4kJ
Solution:- (A) −854.4kJ
Given:-
S+O2⟶SO2ΔH=−398.2kJ.....(1)
SO2+12O2⟶SO3ΔH=−98.7kJ.....(2)
SO3+H2O⟶H2SO4ΔH=−130.2kJ.....(3)
H2+12O2⟶H2OΔH=−227.3kJ.....(4)
Adding eqn(1),(2),(3)&(4), we have
H2+S+2O2⟶H2SO4ΔH=−854.4kJ
Hence the enthalpy of formation of sulphuric acid is −854.4kJ.