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Question

If $S^{o}$ for $H_{2}$ , $C l_{2}$ and HCl are 0.13, 0.22 and 0.19 KJ $K^{- 1} m o l^{- 1}$ respectively. The total change is standard entropy for the reaction,
$H_{2} + C l_{2} \to 2 H C l$ is:

30 J K^{- 1} m o l^{- 1}

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40 J K^{- 1} m o l^{- 1}

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60 J K^{- 1} m o l^{- 1}

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20 J K^{- 1} m o l^{- 1}

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Solution

The correct option is D $30 J K^{- 1} m o l^{- 1}$
The total change in standard entropy $= e n t r o p y o f p r o d u c t s - e n t r o p y o f r e a c t a n t s$

$=$ 2(0.19) - (0.13 + 0.22) is the stoichiometric coefficient of HCl

$= 0.38 - 0.35$

$= 0.03 K J / K m o l$

$= 30 J / K m o l$

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Similar questions

If S⁰ for H₂, Cl₂ and HCL are 0.13, 0.22 and 0.19 kJK^-1mol^-1 respectively. The total change in standard entropy for th2e reaction, H₂+Cl₂→2HCl

S^{0}

H_{2}

{C l}_{2}

K^{- 1} {m o l}^{- 1}

H_{2} + {C l}_{2} ⟶ 2 H C l

If S⁰ for H₂, Cl₂ and HCL are 0.13, 0.22 and 0.19 kJK^-1mol^-1 respectively. The total change in standard entropy for th2e reaction, H₂+Cl₂→2HCl

H_{2} (g) + C l_{2} (g) ⟶ 2 H C l (g)

298 K

S_{H_{2}}^{⊖} = 131 J K^{- 1} m o l^{- 1}

S_{C l_{2}}^{⊖} = 223 J K^{- 1} m o l^{- 1}

S_{H C l}^{⊖} = 187 J K^{- 1} m o l^{- 1}

S_{H_{2}}^{\circ} = 131 J K^{- 1} m o l^{- 1} S_{C l_{2}}^{\circ} = 223 J K^{- 1} m o l^{- 1} a n d S_{H C l}^{\circ} = 187 J K^{- 1} m o l^{- 1}

1

H C l (g)

H_{2} (g)

C l_{2} (g)

H C l

H_{2} + C l_{2} \to 2 H C l

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