wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If sec2π7 and tan2π7 are the roots of the equation ax2+bx+c=0, then the value of 5a2(b2c2)(2ac)2 is

Open in App
Solution

Given : The roots of ax2+bx+c=0 be
α=sec2π7 and β=tan2π7

We know that,
sec2π7tan2π7=1αβ=1(αβ)2=1b24aca2=1b2=a2+4ac(1)

Now,
5a2(b2c2)(2ac)2=5a2(a2+4acc2)(2ac)2=4a24ac+c2(2ac)2=(2ac)2(2ac)2=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon