Question

If $\sec A=\csc A$ and $0^0$ and $0^0\le A\le {90}^0$, state the value of angle $A$ in degrees

Answer 1

$secA=cscA$
$\frac{1}{cosA}=\frac{1}{sinA}$
$\frac{sinA}{cosA}=1$
$tanA=1$
$tanA=tan45$
$A={45}^{\circ }$