Question

If $\tan \theta =\cot \theta$ and $0^0\le \theta \le {90}^0$, state the value of $\theta$ in degrees

Answer 1

$\tan \theta =\cot \theta$

$\tan \theta =\frac{1}{\tan \theta }$

${\tan }^2\theta =1$

$\tan \theta =\pm 1$

Neglecting the negative value,

$\tan \theta =1$

$\tan \theta =\tan 45$

$\theta ={45}^{\circ }$