Question

If Sec A + tan A=x then sec A=?

Answer 1

Solution :-

We are given , SecA+TanA=x ------- (1) equation

We know that Sec²A-Tan²A=1

This is of the form a²-b²=(a+b)(a-b)

So (SecA-TanA)(SecA+TanA)=1

SecA-TanA=1/x {From eq.1}

So Sec A - Tan A = 1 / x ---Lets consider this as Equation 2

Now adding Eq.1 and Eq.2,

we get 2SecA=x+1/x

Hence SecA=(x+1/x)/2

So SecA=(x²+1)/2x Answer.