If SecA + tanA = x. Find secA-tanA in terms of x.

Open in App

Solution

Given secA + tan A = x
Recall the identity, sec2A – tan2A = 1
⇒ (secA + tan A)(secA – tanA) = 1
⇒ x × (secA – tanA) = 1
∴ (secA – tanA) = 1/x

Suggest Corrections

Similar questions

\frac{t a n A}{s e c A - 1} = \frac{t a n A + s e c A + 1}{s e c A - 1 + t a n A}

\frac{s e c A - t a n A}{s e c A + t a n A} = 1 - 2 s e c A t a n A + 2 t a n^{2} A

s e c A = x + \frac{1}{4 x}

s e c A + t a n A = 2 x o r \frac{1}{2 x}

\frac{s e c A - t a n A}{s e c A + t a n A} = \frac{c o s^{2} A}{(1 + s i n A)^{2}}

Join BYJU'S Learning Program

Select...