Question

If $\sec \theta -\tan \theta =8$. Then $\sec \theta +\tan \theta =$

Answer 1

Given: $\sec \theta -\tan \theta =8$

$\Rightarrow {\sec }^2\theta -{\tan }^2\theta =1$

$\Rightarrow (\sec \theta -\tan \theta )$$(\sec \theta +\tan \theta )=1$

$\therefore \sec \theta +\tan \theta =\frac{1}{8}$