Question

If ($sec\theta$ - $tan\theta$) = $\frac{1}{3}$, then value of ($sec\theta$ + $tan\theta$) is:

Answer 1

We know that , $se{c}^2\theta$ - $ta{n}^2\theta$ = 1

Therefore, ($sec\theta$ + $tan\theta$) ($sec\theta$ - $tan\theta$) = 1

Since, ($sec\theta$ - $tan\theta$) = $\frac{1}{3}$

Thus ($sec\theta$ + $tan\theta$) = 3