Question

$\mathrm{If}\sec \theta =x,\mathrm{then}\mathrm{write}\mathrm{the}\mathrm{value}\mathrm{of}\tan \theta .$

Answer 1

$$\begin{gathered} \mathrm{As},{\tan }^2\theta ={\sec }^2\theta -1 \\ \mathrm{So},\tan \theta =\sqrt{{\sec }^2\theta -1}=\sqrt{x^2-1} \end{gathered}$$