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Question

If sin1α+sin1β+sin1γ=3π2, then αβ+αγ+βγ is equal to :

A
1
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B
0
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C
3
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D
3
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Solution

The correct option is B 3
The above expression is true for
α=1 , β=1 and γ=1
Since π2sin1(x)π2
Hence
αβ+βγ+γα
=(1)+(1)+(1)
=3

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