If sin - 1x - sin - 1y - sin - 1z - sin - 1t - 2- then- find the value of x2 - y2 - z2 - t2-

[ sin ^ 1x + sin ^ 1y + sin ^ 1z + sin ^ 1t = 2π; sin ^ 1x = sin ^ 1y = sin ^ 1z = sin ^ 1t = π2; #160;⇒ x = ...

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Domain and Range of Basic Inverse Trigonometric Functions

If sin - 1x...

Question

If ${sin}^{- 1} x + {sin}^{- 1} y + {sin}^{- 1} z + {sin}^{- 1} t = 2 π$ then, find the value of $x^{2} + y^{2} + z^{2} + t^{2}$ .

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{sin}^{- 1} x + {sin}^{- 1} y + {sin}^{- 1} z = \frac{3 π}{2}

x^{2} + y^{2} + z^{2}

s i n^{- 1} x + s i n^{- 1} y + s i n^{- 1} z = \frac{π}{2}, t h e n x^{2} + y^{2} + z^{2} + 2 x y z =

{sin}^{- 1} x + {sin}^{- 1} y + {sin}^{- 1} z = \frac{π}{2},

x^{2} + y^{2} + z^{2} + 2 x y z

s i n^{- 1} x + s i n^{- 1} y + s i n^{- 1} z = \frac{π}{2}, t h e n x^{2} + y^{2} + z^{2} + 2 x y z =

{sin}^{- 1} x + {sin}^{- 1} y + {sin}^{- 1} z = π

x \sqrt{1 - x^{2}} + y \sqrt{1 - y^{2}} + z \sqrt{1 - z^{2}} = 2 x y z

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