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Value of Standard Angle(30,60,90)

If sin 3 θ=co...

Question

If sin 3 θ = cos (θ − 6°), where 3 θ and θ − 6° are acute angles, find the value of θ.

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Solution

We have: where and are acute angles

We have to find

Now we proceed as to find

Therefore

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If cos $3 θ = c o s θ - 6^{o}$ ,where 3 $θ$ and $θ - 6^{o}$ are acute angles, find the value of $θ$

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