If sin3x−2sin2x−(K+1)sinx+2−K=0; sinx≠−1posses a solution for finite integral values of K only, then the number of positive integral value of K are equal to
A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 5 (sin2x−3sinx+2)(sinx+1)=K(sinx+1) K=(sinx−32)2−14 Kϵ[0,6);(K≠6∵sinx≠=−1) K={1,2,3,4,5}