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Question

If sin3 x2 sin2 x(K+1) sin x+2K=0; sin x1 posses a solution for finite integral values of K only, then the number of positive integral value of K are equal to

A
4
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B
5
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C
6
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D
7
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Solution

The correct option is B 5
(sin2 x3 sin x+2)(sin x+1)=K(sin x+1)
K=(sin x32)214
Kϵ[0,6); (K6 sin x=1)
K={1,2,3,4,5}

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