If $sin A + cos A = 1$ , then $sin 2 A =$

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Solution

The correct option is D $0$
$sin A + cos A = 1$
Squaring on both sides
${(sin A + cos A)}^{2} = 1$
${sin}^{2} A + {cos}^{2} A + 2 sin A cos A = 1$
$1 + sin 2 A = 1$
$sin 2 A = 0$

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