Question

If $\sin A=\frac{3}{5}$ and $\cos A=\frac{4}{5}$ then, $\tan A=$

Answer 1

We know that $\tan x$ is $\sin x$ over $\cos x$ that is $\tan x=\frac{\sin x}{\cos x}$.

Here, it is given that $\sin A=\frac{3}{5}$ and $\cos A=\frac{4}{5}$, therefore,

$\tan A=\frac{\sin A}{\cos A}=\frac{\frac{3}{5}}{\frac{4}{5}}=\frac{3}{5}\times \frac{5}{4}=\frac{3}{4}$

Hence, $\tan A=\frac{3}{4}$.