If sin α, cos α are the roots of the equation ax2 + bx + c = 0, then
As given, sin α + cos α = -ba, sinα cos α = ca
To eliminate α, we have
1 = sin2 α + cos2α = (sinα+cosα)2 - 2 sin α cos α
= b2a2 - 2ca ⇒ a2 - b2 + 2ac = 0