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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
If sinα = 1...
Question
If
sin
α
=
1
2
and
cos
β
=
1
2
, then
(
α
+
β
)
=
.
.
.
.
.
.
.
.
.
.
A
0
∘
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B
30
∘
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C
60
∘
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D
90
∘
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Solution
The correct option is
B
90
∘
sin
α
=
1
2
⇒
sin
α
=
sin
30
∘
⇒
α
=
30
∘
cos
β
=
1
2
⇒
cos
β
=
cos
60
∘
⇒
β
=
60
∘
So,
(
α
+
β
)
=
60
o
+
30
o
=
90
o
Therefore, Answer is
90
o
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1
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Q.
Question 10
If
s
i
n
α
=
1
2
and
c
o
s
β
=
1
2
, then the value of
(
α
+
β
)
is
(A)
0
∘
(B)
30
∘
(C)
60
∘
(D)
90
∘
Q.
If sin α =
1
2
and cos β =
1
2
, then (α + β) = ?
(a) 0°
(b) 30°
(c) 60°
(d) 90°
Q.
If
s
i
n
α
=
c
o
s
(
90
°
−
β
)
=
1
√
2
and
0
°
≤
α
,
β
≤
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°
, then find
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+
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.
Q.
If
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o
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+
c
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i
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0
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+
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o
s
(
γ
+
α
)
+
c
o
s
(
α
+
β
)
=
0
s
i
n
(
β
+
γ
)
s
i
n
(
γ
+
α
)
+
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Given that
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