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Byju's Answer
Standard XII
Mathematics
Implicit Differentiation
If sinα= 45...
Question
If
sin
α
=
4
5
and
sin
β
=
7
25
and
α
β
∈
(
0
,
π
2
)
then value of
sin
−
1
(
4
5
)
+
sin
−
1
(
7
25
)
=
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Solution
now
c
o
s
α
=
3
5
,
c
o
s
β
=
24
25
s
i
n
(
α
+
β
)
=
s
i
n
α
c
o
s
β
+
s
i
n
β
c
o
s
α
=
96
125
+
21
125
=
117
125
s
i
n
(
α
+
β
)
=
117
125
α
+
β
=
s
i
n
−
1
(
117
125
)
s
i
n
−
1
(
4
5
)
+
s
i
n
−
1
(
7
25
)
=
s
i
n
−
1
(
117
125
)
Suggest Corrections
0
Similar questions
Q.
Prove that
sin
−
1
4
5
+
sin
−
1
7
25
=
sin
−
1
117
125
Q.
It is known that
sin
β
=
4
5
&
0
<
β
<
π
then the value of
√
3
sin
(
α
+
β
)
−
2
cos
π
6
cos
(
α
+
β
)
sin
α
is
Q.
If sin
α
= 5/13 and sin
β
=
4
5
then the value of cos
α
cos
β
- sin
α
sin
β
is
Q.
If
α
,
β
,
γ
∈
(
0
,
π
2
)
then the value of
sin
(
α
+
β
+
γ
)
sin
α
+
sin
β
+
sin
γ
is
Q.
If
sin
α
=
15
17
,
π
2
<
α
<
π
and
cos
β
=
−
4
5
,
π
<
β
<
3
π
2
Find
sin
(
α
−
β
)
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