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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
If sin α = 1/...
Question
Question 10
If
s
i
n
α
=
1
2
and
c
o
s
β
=
1
2
, then the value of
(
α
+
β
)
is
(A)
0
∘
(B)
30
∘
(C)
60
∘
(D)
90
∘
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Solution
The answer is (D).
Given,
G
i
v
e
n
,
s
i
n
α
=
1
2
=
s
i
n
30
∘
[
∵
s
i
n
30
∘
=
1
2
]
⇒
α
=
30
∘
And
c
o
s
β
=
1
2
=
c
o
s
60
∘
[
∵
c
o
s
60
∘
=
1
2
]
⇒
β
=
60
∘
∴
α
+
β
=
30
∘
+
60
∘
=
90
∘
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Similar questions
Q.
If sin α =
1
2
and cos β =
1
2
, then (α + β) = ?
(a) 0°
(b) 30°
(c) 60°
(d) 90°
Q.
If
sin
α
=
1
2
and
cos
β
=
1
2
, then
(
α
+
β
)
=
.
.
.
.
.
.
.
.
.
.
Q.
Given that
sin
α
=
1
2
and
cos
β
=
1
2
, then the value of
(
α
+
β
)
is:
Q.
If
s
i
n
α
=
c
o
s
(
90
°
−
β
)
=
1
√
2
and
0
°
≤
α
,
β
≤
90
°
, then find
α
+
β
.
Q.
If
sin
α
−
sin
β
=
1
/
3
and
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β
−
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=
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then
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α
+
β
2
=
k
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. Find the value of
k
.
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Range of Trigonometric Ratios from 0 to 90 Degrees
Standard X Mathematics
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