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Question

If sinα+sinβ=a and cosα+cosβ=b
then show that, sin(α+β)=2aba2+b2.

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Solution

sin(α+β)=2aba2+b2a=sinα+sinβ=2sin(α+β2).cos(αβ2)b=cosα+cosβ=2cos(α+β2).cos(αβ2)ab=4sin(α+β2).cos(α+β2).cos(αβ2)=2sin(α+β).cos2(αβ2)a2+b2=4cos2(αβ2)2aba2+b2=sin(α+β)proved.

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