Question

If sin θ + cos θ = 1 and 0° ≤ θ ≤ 90°, then the possible values of θ are ________.

Answer 1

The given equation is sinθ + cosθ = 1.

When θ = 0°,

LHS = sinθ + cosθ = sin0° + cos0° = 0 + 1 = 1 = RHS

When θ = 90°,

LHS = sinθ + cosθ = sin90° + cos90° = 1 + 0 = 1 = RHS

Thus, the possible values of θ (0° ≤ θ ≤ 90°) satisfying the given equation are 0° and 90°.

If sin θ + cos θ = 1 and 0° ≤ θ ≤ 90°, then the possible values of θ are _0° and 90°_.