Question

If $\sin \theta +2\cos \theta =1$ then prove that $2\sin \theta -\cos \theta =0$.

Answer 1

Given,

$\sin \theta +2\cos \theta =1$.

Now differentiating both sides with respect to $\theta$ we get,

$\cos \theta -2\sin \theta =0$

or, $2\sin \theta -\cos \theta =0$.