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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Common Angles
If sinθ + c...
Question
If
sin
θ
+
cos
θ
=
1
, then
sin
θ
cos
θ
equal to :
A
0
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B
1
√
3
−
1
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C
1
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D
1
+
√
2
1
+
√
3
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Solution
The correct option is
D
0
Let
sin
θ
+
cos
θ
=
1
Squaring both side, we get
sin
2
θ
+
cos
2
θ
+
2
sin
θ
cos
θ
=
1
⇒
sin
θ
cos
θ
=
0
Hence, option 'A' is correct.
Suggest Corrections
0
Similar questions
Q.
Prove the following trigonometric identities.
(i)
sec
θ
-
1
sec
θ
+
1
+
sec
θ
+
1
sec
θ
-
1
=
2
cosec
θ
(ii)
1
+
sin
θ
1
-
sin
θ
+
1
-
sin
θ
1
+
sin
θ
=
2
sec
θ
(iii)
1
+
cos
θ
1
-
cos
θ
+
1
-
cos
θ
1
+
cos
θ
=
2
cosec
θ
(iv)
sec
θ
-
1
sec
θ
+
1
=
sin
θ
1
+
cos
θ
2
(v)
sin
θ
+
1
-
cos
θ
cos
θ
-
1
+
sin
θ
=
1
+
sin
θ
cos
θ