If -1369-0-0615- x -37-25- find the value of x-A- 10-1B- 10-2- 10D- 10-3

The correct option is D 10^ 3 √(1369) + √(0.0615+x) = 37.25 ⇒√(0.0615+x)=37.25 √(1369) ⇒√(0.0615+x) =37.25 37 = 0.25 ⇒ 0.0615 + x =(0.25)^2 = 0.0625 ⇒ x = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Power of a Power

If √1369+√0.0...

Question

If $\sqrt{1369} + \sqrt{0.0615 + x} = 37.25$ , find the value of $x$ ?

$10^{- 1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10^{- 2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10^{- 3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$10$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$10^{- 3}$

$\sqrt{1369} + \sqrt{0.0615 + x} = 37.25$
$\Rightarrow \sqrt{0.0615 + x} = 37.25 - \sqrt{1369}$
$\Rightarrow \sqrt{0.0615 + x} = 37.25 - 37 = 0.25$
$\Rightarrow 0.0615 + x = (0.25)^{2} = 0.0625$
$\Rightarrow x = 0.0625 - 0.0615 = 0.001 = \frac{1}{10^{3}} = 10^{- 3}$

Suggest Corrections

Similar questions

If $\sqrt{1369} + \sqrt{0.0615 + x} = 37.25$ . Find the value of $x$ .

Q. If

\sqrt{1369} + \sqrt{0.0615 + x} = 37.25

, then

x

is equal to

Q. If

\sqrt{1369} + \sqrt{0.0615 + x} = 37.25

, find the value of

x

Q. If 0⁰ < x < 90^o and cos

then log₁₀ sin x + log ₁₀ cos x + log ₁₀ tan x is equal to

If $l o g_{\sqrt{8}} x = \frac{10}{3}$ , find the value of x

Join BYJU'S Learning Program

If √1369+√0.0615+x=37.25, find the value of x?

The correct option is C 10−3 √1369+√0.0615+x=37.25 ⇒√0.0615+x=37.25−√1369 ⇒√0.0615+x=37.25−37=0.25 ⇒0.0615+x=(0.25)2=0.0625 ⇒x=0.0625−0.0615=0.001=1103=10−3

If $\sqrt{1369} + \sqrt{0.0615 + x} = 37.25$ , find the value of $x$ ?