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Question

If standard enthalpies of formation of CaCl(s) (hypothetical) and that of CaCl2(s) are 188 Jmol1 and 795 Jmol1 respectively. Calculate the value of standard heat of reaction for the following disproportionation reaction.


2CaCl(s)CaCl2(s)+Ca(s)

A
607 kJmol1
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B
+607 kJmol1
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C
419 kJmol1
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D
+419 kJmol1
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Solution

The correct option is C 419 kJmol1
2Ca+1Cl(s)Ca+2Cl2(s)+Ca0

In disproportionation reaction same species (here Ca2+) is oxidized as well as reduced.

Standard heat of reaction, ΔHo=ΔHoPΔHoR

=ΔHof(CaCl2)+ΔHof(Ca)2ΔHof(CaCl)=419kJ mol1

Hence, option C is correct.

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