If standard enthalpies of formation of CaCl(s) (hypothetical) and that of CaCl2(s) are −188Jmol−1 and −795Jmol−1 respectively. Calculate the value of standard heat of reaction for the following disproportionation reaction.
2CaCl(s)⟶CaCl2(s)+Ca(s)
A
−607kJmol−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
+607kJmol−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−419kJmol−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
+419kJmol−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C−419kJmol−1
2Ca+1Cl(s)→Ca+2Cl2(s)+Ca0
In disproportionation reaction same species (here Ca2+) is oxidized as well as reduced.