If $\sum d^{2} = 66$ and $n = 10$ then find the rank correlation coefficient.

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Solution

$\sum d^{2} = 66 n = 10$
We know rank $r = 1 - \frac{6 \sum d^{2}}{n (n^{2} - 1)}$
Or $1 - \frac{6 \times 66}{10 (99)}$
Or $1 - \frac{6 \times 2}{30}$
Or $1 - \frac{2}{5}$
Or $\frac{3}{5}$
$∴ r = \frac{3}{5}$

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If ∑d2=66 and n=10 then find the rank correlation coefficient.

∑d2=66n=10We know rank r=1−6∑d2n(n2−1)Or 1−6×6610(99)Or 1−6×230Or 1−25Or 35∴r=35

If $\sum d^{2} = 66$ and $n = 10$ then find the rank correlation coefficient.

$\sum d^{2} = 66 n = 10$
We know rank $r = 1 - \frac{6 \sum d^{2}}{n (n^{2} - 1)}$
Or $1 - \frac{6 \times 66}{10 (99)}$
Or $1 - \frac{6 \times 2}{30}$
Or $1 - \frac{2}{5}$
Or $\frac{3}{5}$
$∴ r = \frac{3}{5}$